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A086581
Number of Dyck paths of semilength n with no DDUU.
11
1, 1, 2, 5, 13, 35, 97, 275, 794, 2327, 6905, 20705, 62642, 190987, 586219, 1810011, 5617914, 17518463, 54857506, 172431935, 543861219, 1720737981, 5459867166, 17369553427, 55391735455, 177040109419, 567019562429, 1819536774089
OFFSET
0,3
COMMENTS
See A025242 for a bijection between paths avoiding UUDD versus DDUU.
Number of lattice paths, never going below the x-axis, from (0,0) to (n,0) consisting of up steps U(k) = (k,1) for every positive integer k, down steps D = (1,-1) and horizontal steps H. - José Luis Ramírez Ramírez, Apr 19 2015
Given a sequence variant with 0 inserted between the two 1's, the INVERT transform of the modified sequence is this sequence. - Gary W. Adamson, Jun 28 2015
LINKS
Lu, Qing Lin Skew Motzkin paths Acta Math. Sin., Engl. Ser. 33, No. 5, 657-667 (2017) sequence s_n
T. Mansour, Restricted 1-3-2 permutations and generalized patterns, arXiv:math/0110039 [math.CO], 2001.
T. Mansour, Restricted 1-3-2 permutations and generalized patterns, Annals of Combin., 6 (2002), 65-76. (Example 2.10.)
L. Pudwell, Pattern avoidance in trees (slides from a talk, mentions many sequences), 2012. - From N. J. A. Sloane, Jan 03 2013
A. Sapounakis, I. Tasoulas and P. Tsikouras, On the Dominance Partial Ordering of Dyck Paths, Journal of Integer Sequences, Vol. 9 (2006), Article 06.2.5.
A. Sapounakis, I. Tasoulas and P. Tsikouras, Counting strings in Dyck paths, Discrete Math., 307 (2007), 2909-2924.
Murray Tannock, Equivalence classes of mesh patterns with a dominating pattern, MSc Thesis, Reykjavik Univ., May 2016.
FORMULA
G.f. A(x) satisfies the equation 0 = 1 - x - (1 - x)^2 * A(x) + (x * A(x))^2.
a(n) = A025242(n+1) = A082582(n+1).
G.f.: (1 - 2*x + x^2 - sqrt(1 - 4*x + 2*x^2 + x^4)) /(2 * x^2).
a(n+2) - 2*a(n+1) + a(n) = a(0)*a(n) + a(1)*a(n-1) + ... + a(n)*a(0).
G.f.: (1/(1-x))*c(x^2/(1-x)^3), c(x) the g.f. of A000108; a(n)=sum{k=0..floor(n/2), C(n+k,3k)*A000108(k)}. - Paul Barry, May 31 2006
Conjecture: (n+2)*a(n) +(n+3)*a(n-1) +2*(-9*n+4)*a(n-2) +10*(n-2)*a(n-3) +(n-4)*a(n-4) +5*(n-5)*a(n-5)=0. - R. J. Mathar, Nov 26 2012
G.f. satisfies (10*x^3-28*x^2+4*x+2)*A(x) + (5*x^6+x^5+10*x^4-18*x^3+x^2+x)*A'(x) = 5*x^4+x^3-15*x^2+7*x+2. This confirms R. J. Mathar's recurrence equation. - Robert Israel, Jun 29 2015
G.f.: 1 - G(0), where G(k)= 1 - 1/(1 - x/(1 - x/(1 - x/(1 - x/(x - 1/G(k+1) ))))); (continued fraction). - Sergei N. Gladkovskii, Jul 12 2013
G.f.: 1/G(0) where G(k) = 1 - q/(1 - q - q^2 / G(k+1) ); (continued fraction). - Joerg Arndt, Feb 27 2014
From Thomas Baruchel, Jan 19 2015: (Start)
a(n) = 1+Sum_{k=0..n} Sum_{i=0..k} C(n-1,k)*C(2i+2,i)*C(i+2,k-2i-1)/(i+1).
a(n) = Sum_{k=0..n} C(2k,k)*C(n+k,3k)/(k+1).
Sum_{k=0..n} a(k+1)*A108626(n-k) = Sum_{k=0..n} Sum_{i=0..k} binomial(n-k+1,i-1)*binomial(n-k+1,i)*binomial(n-i+1,k-i). (End)
EXAMPLE
a(4) = 13 because of the 14 Dyck 4-paths only UUDDUUDD contains DDUU.
MAPLE
F:= gfun:-rectoproc({(n+2)*a(n) +(n+3)*a(n-1) +2*(-9*n+4)*a(n-2) +10*(n-2)*a(n-3) +(n-4)*a(n-4) +5*(n-5)*a(n-5)=0, seq(a(n)=[1, 1, 2, 5, 13][n+1], n=0..4)}, a(n), remember):
map(F, [$0..30]); # Robert Israel, Jun 29 2015
MATHEMATICA
CoefficientList[ Series[(1 - 2 x + x^2 - Sqrt[1 - 4 x + 2 x^2 + x^4])/(2 x^2), {x, 0, 27}], x] (* Robert G. Wilson v, Mar 25 2011 *)
PROG
(PARI) {a(n) = polcoeff((1 - 2*x + x^2 - sqrt(1 - 4*x + 2*x^2 + x^4 + x^3 * O(x^n))) / 2, n+2)}
(PARI) a(n)=1+sum(k=0, n, sum(i=0, k, binomial(n-1, k)*binomial(2*i+2, i)*binomial(i+2, k-2*i-1)/(i+1))) \\ Thomas Baruchel, Jan 19 2015
CROSSREFS
Column k=0 of A114492.
Sequence in context: A007689 A085281 A082582 * A059027 A025198 A221205
KEYWORD
nonn
AUTHOR
Michael Somos, Jul 22 2003
EXTENSIONS
Name corrected by David Scambler, Mar 28 2011
STATUS
approved