A084819 Least integers that satisfy Sum_{n>=1} 1/a(n)^z = 0, where a(1)=1, a(n+1) > a(n) and z = i*Pi/(4*log(2)).

1, 7, 18, 51, 147, 423, 1224, 3543, 10254

Offset

1,2

Comments

Sequence satisfies Sum_{n>=1} 1/a(n)^z = 0 by requiring that the moduli of the successive partial sums are monotonically decreasing in magnitude for the given z.

Links

Table of n, a(n) for n=1..9.

Prog

(PARI) S=0; w=1; a=0; for(n=1, 100, b=a+1; while(abs(S+exp(-z*log(b)))>w, b++); S=S+exp(-z*log(b)); w=abs(S); a=b; print1(b, ", "))

Crossrefs

Cf. A084812, A084813, A084814, A084815, A084816, A084817, A084818.

Sequence in context: A324900 A343545 A324944 * A346494 A220031 A197092

Adjacent sequences: A084816 A084817 A084818 * A084820 A084821 A084822

Keyword

nonn,more

Author

Paul D. Hanna, Jun 04 2003

Status

approved