A084815 Least integers that satisfy Sum_{n>=1} 1/a(n)^z = 0, where a(1)=1, a(n+1) > a(n) and z = i*Pi/4.

1, 15, 57, 226, 896, 3556, 14114

Offset

1,2

Comments

Sequence satisfies Sum_{n>=1} 1/a(n)^z = 0 by requiring that the modulus of the successive partial sums are monotonically decreasing in magnitude for the given z.

Links

Table of n, a(n) for n=1..7.

Prog

(PARI) S=0; w=1; a=0; for(n=1, 100, b=a+1; while(abs(S+exp(-z*log(b)))>w, b++); S=S+exp(-z*log(b)); w=abs(S); a=b; print1(b, ", "))

Crossrefs

Cf. A084812-A084814, A084816-A084818.

Sequence in context: A336251 A158482 A184223 * A240152 A261419 A183942

Adjacent sequences: A084812 A084813 A084814 * A084816 A084817 A084818

Keyword

nonn,more

Author

Paul D. Hanna, Jun 04 2003

Status

approved