

A078117


Let u(1)=n, u(2)=n+1, v(1)=n+2, v(2)=n+3, u(k)=abs(u(k1)v(k2)), v(k)=abs(v(k1)u(k2)), then a(n) is the smallest integer such that for any k>=a(n), v(k)=u(k).


0



8, 11, 15, 17, 15, 11, 12, 14, 12, 14, 9, 14, 12, 17, 21, 23, 21, 16, 18, 20, 18, 20, 15, 20, 18, 23, 27, 29, 27, 22, 24, 26, 24, 26, 21, 26, 24, 29, 33, 35, 33, 28, 30, 32, 30, 32, 27, 32, 30, 35, 39, 41, 39, 34, 36, 38, 36, 38, 33, 38, 36, 41, 45, 47, 45, 40, 42, 44, 39, 44
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OFFSET

1,1


LINKS



FORMULA

a(n)/n > 1/2; for n>= 7, a(n) = (1/2)*(n+b(n)) where b(n) is the 12periodic sequence (17, 20, 15, 18, 7, 16, 11, 20, 27, 30, 25, 14)


CROSSREFS



KEYWORD

nonn


AUTHOR



STATUS

approved



