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A073363
Nested floor product of n and fractions (k+1)/k for all k>0 (mod 6), divided by 6.
1
1, 7, 28, 84, 175, 421, 847, 1288, 1939, 3780, 5656, 9247, 15148, 22099, 25375, 39676, 54607, 75208, 90559, 129360, 166321, 209832, 240268, 320719, 399595, 536956, 672672, 816733, 906444, 1115275, 1321741, 1595832, 1908088, 2323944
OFFSET
1,2
COMMENTS
When is a(n) not divisible by 7?
FORMULA
a(n)=(1/6)[...[[[[[[n(2/1)](3/2)](4/3)](5/4)](6/5)](8/7]...(k+1)/k]..., k>0 (mod 6), where [x] = floor of x; this infinite nested floor product will eventually level-off at a(n).
EXAMPLE
a(1)=1 since (1/6)[[[[1(2/1)](3/2)](4/3)](5/4)](6/5)]=1
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Paul D. Hanna, Jul 29 2002
STATUS
approved