OFFSET
1,2
COMMENTS
The sum of the reciprocals of the upper bound twin primes is convergent. Proof: If S2 = 1/5 + 1/7 + 1/13 + 1/19 . . . is divergent then S2 + (S1 = 1/3 + 1/5 + 1/11 + 1/17 . . .) is divergent. But S1+S2 = 1/3+1/5 + 1/5+1/7 + 1/11+1/13 ... was proved to be convergent by V. Brun in 1919. So S2 is not divergent and since it is not oscillating, it is convergent as stated.
FORMULA
a(n) = numerator(Sum_{k=1..n} 1 / A006512(k)). - Sean A. Irvine, Aug 25 2024
EXAMPLE
1/5+1/7+1/13+1/19 = 4084/8645 and 4084 is the fourth entry in the table.
PROG
(PARI) \\ Sum of the reciprocals of lower bound of twin primes
{ p=1; for(y=1, n, z=sum(x=1, y, 1/(twin[x]+2)^p); print1(numerator(z)", ") ); print(); print(z+.0); }
\\ Build a twin prime table of lower bounds. Run only once in a session
savetwins(n) = { twin = vector(n); c=1; forprime(x=3, n*10, if(isprime(x+2), twin[c]=x; c++; ) ) }
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Cino Hilliard, Jan 23 2004
EXTENSIONS
Offset corrected and more terms from Sean A. Irvine, Aug 25 2024
STATUS
approved