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A070275
Numbers k such that the sum of the digits of k equals the sum of the prime divisors of k.
13
2, 3, 5, 7, 84, 160, 250, 336, 468, 735, 936, 975, 1344, 1375, 1408, 1600, 1694, 1872, 2352, 2401, 2500, 2625, 2808, 3744, 3920, 4116, 4913, 5145, 5616, 6084, 6318, 7296, 7497, 7695, 8424, 8624, 8664, 8704, 9126, 9639, 10240, 12168, 12636, 12675, 14896
OFFSET
1,1
COMMENTS
If k=10^s*m is a term of the sequence where s > 0 and gcd(m,10)=1, then for each positive integer j, 10^j*m is in the sequence, because the sum of the digits of 10^j*k equals the sum of the digits of k and the sum of the distinct prime factors of 10^j*k equals the sum of the distinct prime factors of k. Also it is obvious that m isn't in the sequence. - Jahangeer Kholdi, Oct 07 2013
LINKS
MATHEMATICA
Rest[Select[Range[20000], Total[Transpose[FactorInteger[#]][[1]]] == Total[ IntegerDigits[#]] &]] (* Harvey P. Dale, Dec 15 2010 *)
PROG
(PARI) isok(n) = sumdigits(n) == vecsum(factor(n)[, 1]); \\ Michel Marcus, May 27 2018
KEYWORD
easy,nonn,base
AUTHOR
Benoit Cloitre, May 09 2002
STATUS
approved