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A050689
Composites whose sum of digits equals number of its prime factors, with multiplicity.
10
12, 30, 32, 40, 102, 220, 240, 500, 600, 1002, 1012, 1104, 1152, 1210, 1320, 1500, 2001, 2002, 2020, 2040, 2120, 2240, 2300, 3010, 3040, 3300, 4032, 4100, 4320, 5100, 5200, 6400, 7000, 7200, 10001, 10002, 10011, 10030, 10040, 10080, 10140, 10220, 10304, 10800
OFFSET
1,1
COMMENTS
The sequence is infinite because there are infinitely many primes whose sum of digits is odd (see related comment in A119450). Let p be one of them, and let k be its digital sum. Then p*10^((k-1)/2) is a term. For example, 41*10^2 is a term. - Metin Sariyar, May 30 2020
LINKS
Giovanni Resta, Table of n, a(n) for n = 1..10000 (first 322 terms from Michael Turniansky)
EXAMPLE
2002 is a term since 2+0+0+2 = 4, and 2002 = 2*7*11*13 has 4 prime factors.
MATHEMATICA
Select[Range[10300], !PrimeQ[#]&&PrimeOmega[#]==Total[IntegerDigits[#]]&] (* Jayanta Basu, May 30 2013 *)
PROG
(APL (NARS200 dialect)) ⍸∊{(⍴π⍵)=+/(10⍴10)⊤⍵}¨⍳1E6 ⍝for the numbers through 1000000 Michael Turniansky Feb 13 2017
(PARI) isok(n) = sumdigits(n) == bigomega(n); \\ Michel Marcus, Feb 13 2017
(Python)
from sympy import factorint
def ok(n): return 1 < sum(map(int, str(n))) == sum(factorint(n).values())
print([k for k in range(11000) if ok(k)]) # Michael S. Branicky, Dec 30 2021
KEYWORD
nonn,base
AUTHOR
Patrick De Geest, Aug 15 1999
STATUS
approved