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A064532 Total number of holes in decimal expansion of the number n, assuming 4 has no hole. 9
1, 0, 0, 0, 0, 0, 1, 0, 2, 1, 1, 0, 0, 0, 0, 0, 1, 0, 2, 1, 1, 0, 0, 0, 0, 0, 1, 0, 2, 1, 1, 0, 0, 0, 0, 0, 1, 0, 2, 1, 1, 0, 0, 0, 0, 0, 1, 0, 2, 1, 1, 0, 0, 0, 0, 0, 1, 0, 2, 1, 2, 1, 1, 1, 1, 1, 2, 1, 3, 2, 1, 0, 0, 0, 0, 0, 1, 0, 2, 1, 3, 2, 2, 2, 2, 2, 3, 2, 4, 3, 2, 1, 1, 1, 1, 1, 2, 1, 3, 2, 2, 1, 1, 1, 1 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,9
COMMENTS
Assumes that 4 is represented without a hole.
LINKS
FORMULA
a(10i+j) = a(i) + a(j), etc.
EXAMPLE
8 has two holes so a(8) = 2.
MATHEMATICA
a[n_ /; 0 <= n <= 9] := a[n] = {1, 0, 0, 0, 0, 0, 1, 0, 2, 1}[[n + 1]]; a[n_] := Total[a[#] + 1 & /@ (id = IntegerDigits[n])] - Length[id]; Table[a[n], {n, 0, 104}] (* Jean-François Alcover, Nov 22 2013 *)
Table[DigitCount[x].{0, 0, 0, 0, 0, 1, 0, 2, 1, 1}, {x, 0, 104}] (* Michael De Vlieger, Feb 02 2017, after Zak Seidov at A064692 *)
PROG
(Python)
def A064532(n):
x=str(n)
return x.count("0")+x.count("6")+x.count("8")*2+x.count("9") # Indranil Ghosh, Feb 02 2017
(PARI) h(n) = [1, 0, 0, 0, 0, 0, 1, 0, 2, 1][n];
a(n) = if (n, my(d=digits(n)); sum(i=1, #d, h(d[i]+1)), 1); \\ Michel Marcus, Nov 11 2022
CROSSREFS
Cf. A064529, A064530. Equals A064531 - 1.
Cf. A358439 (sum by number of digits).
Sequence in context: A106822 A203905 A309142 * A321922 A362496 A360003
KEYWORD
nonn,easy,base
AUTHOR
N. J. A. Sloane, Oct 07 2001
EXTENSIONS
More terms from Matthew Conroy, Oct 09 2001
STATUS
approved

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Last modified May 26 10:56 EDT 2024. Contains 372824 sequences. (Running on oeis4.)