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A061417
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Number of permutations up to cyclic rotations; permutation siteswap necklaces.
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16
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1, 2, 4, 10, 28, 136, 726, 5100, 40362, 363288, 3628810, 39921044, 479001612, 6227066928, 87178295296, 1307675013928, 20922789888016, 355687438476444, 6402373705728018, 121645100594641896, 2432902008177690360, 51090942175425331320, 1124000727777607680022
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OFFSET
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1,2
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COMMENTS
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If permutations are converted to (i,p(i)) permutation arrays, then this automorphism is obtained by their "SW-NE diagonal toroidal shifts" (see Matthias Engelhardt's Java program in A006841), while the Maple procedure below converts each permutation to a siteswap pattern (used in juggling), rotates it by one digit and converts the resulting new (or same) siteswap pattern back to a permutation.
When the subset of permutations listed by A064640 are subjected to the same automorphism one gets A002995.
The number of conjugacy classes of the symmetric group of degree n when conjugating only with the cyclic permutation group of degree n. - Attila Egri-Nagy, Aug 15 2014
Also the number of equivalence classes of permutations of {1...n} under the action of rotation of vertices in the cycle decomposition. The corresponding action on words applies m -> m + 1 for m < n and n -> 1, and rotates once to the right. For example, (24531) first becomes (35142) under the application of cyclic rotation, and then is rotated right to give (23514). - Gus Wiseman, Mar 04 2019
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LINKS
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FORMULA
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a(n) = (1/n)*Sum_{d|n} phi(n/d)*((n/d)^d)*(d!).
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EXAMPLE
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If I have a five-element permutation like 25431, in cycle notation (1 2 5)(3 4), I mark the numbers 1-5 clockwise onto a circle and draw directed edges from 1 to 2, from 2 to 5, from 5 to 1 and a double-way edge between 3 and 4. All the 5-element permutations that produce some rotation (discarding the labels of the nodes) of that chord diagram belong to the same equivalence class with 25431. The sequence gives the count of such equivalence classes.
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MAPLE
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Algebraic formula: with(numtheory); SSRPCC := proc(n) local d, s; s := 0; for d in divisors(n) do s := s + phi(n/d)*((n/d)^d)*(d!); od; RETURN(s/n); end;
Empirically: with(group); SiteSwapRotationPermutationCycleCounts := proc(upto_n) local b, u, n, a, r; a := []; for n from 1 to upto_n do b := []; u := n!; for r from 0 to u-1 do b := [op(b), 1+PermRank3R(SiteSwap2Perm1(rotateL(Perm2SiteSwap2(PermUnrank3Rfix(n, r)))))]; od; a := [op(a), CountCycles(b)]; od; RETURN(a); end;
PermUnrank3Rfixaux := proc(n, r, p) local s; if(0 = n) then RETURN(p); else s := floor(r/((n-1)!)); RETURN(PermUnrank3Rfixaux(n-1, r-(s*((n-1)!)), permul(p, [[n, n-s]]))); fi; end;
PermUnrank3Rfix := (n, r) -> convert(PermUnrank3Rfixaux(n, r, []), 'permlist', n);
SiteSwap2Perm1 := proc(s) local e, n, i, a; n := nops(s); a := []; for i from 1 to n do e := ((i+s[i]) mod n); if(0 = e) then e := n; fi; a := [op(a), e]; od; RETURN(convert(invperm(convert(a, 'disjcyc')), 'permlist', n)); end;
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MATHEMATICA
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a[n_] := (1/n)*Sum[ EulerPhi[n/d]*(n/d)^d*d!, {d, Divisors[n]}]; Table[a[n], {n, 1, 21}] (* Jean-François Alcover, Oct 09 2012, from formula *)
Table[Length[Select[Permutations[Range[n]], #==First[Sort[NestList[RotateRight[#/.k_Integer:>If[k==n, 1, k+1]]&, #, n-1]]]&]], {n, 8}] (* Gus Wiseman, Mar 04 2019 *)
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PROG
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(Haskell)
(GAP) List([1..10], n->Size( OrbitsDomain( CyclicGroup(I sPermGroup, n), SymmetricGroup( IsPermGroup, n), \^))); # Attila Egri-Nagy, Aug 15 2014
(PARI) a(n) = (1/n)*sumdiv(n, d, eulerphi(n/d)*(n/d)^d*d!); \\ Indranil Ghosh, Apr 10 2017
(Python)
from sympy import divisors, factorial, totient
def a(n):
return sum(totient(n//d)*(n//d)**d*factorial(d) for d in divisors(n))//n
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CROSSREFS
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A064636 (derangements-the same automorphism).
Cf. A000031, A000939, A002995, A008965, A060223, A064640, A086675 (digraphical necklaces), A179043, A192332, A275527 (path necklaces), A323858, A323859, A323870, A324513, A324514 (aperiodic permutations).
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KEYWORD
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nonn,easy,nice
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AUTHOR
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STATUS
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approved
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