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A059391
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a(1)=4; a(n) is the smallest number m > a(n-1) such that Omega(m + a(i)) = Omega(m) - Omega(a(i)) for i = 1..(n-1) where Omega(k) is the number of prime divisors of k counted with multiplicity.
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1
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OFFSET
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1,1
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COMMENTS
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Conjecture: Omega(a(n)) = n-th prime.
The conjecture is false because Omega(780856896) = 10. - Sean A. Irvine, Sep 19 2022
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LINKS
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CROSSREFS
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KEYWORD
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nonn,hard,more
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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