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A056942
Area of rectangle needed to enclose a non-touching spiral of length n on a square lattice.
3
0, 1, 2, 4, 6, 6, 9, 12, 12, 12, 16, 20, 20, 20, 20, 25, 30, 30, 30, 30, 30, 36, 42, 42, 42, 42, 42, 42, 49, 56, 56, 56, 56, 56, 56, 56, 64, 72, 72, 72, 72, 72, 72, 72, 72, 81, 90, 90, 90, 90, 90, 90, 90, 90, 90, 100, 110, 110, 110, 110, 110, 110, 110, 110, 110, 110, 121
OFFSET
0,3
COMMENTS
m^2 (when n is m-th triangular number) followed by m copies of m-th pronic [m(m+1)].
LINKS
FORMULA
a(n) = floor[(sqrt(8n+1)-1)/2]*ceiling[(sqrt(8n+1)-1)/2] = A002024(n)*A003056(n) = A056943(n)+n = 2n-A056944(n). If n = t(t+1)/2 then a(n) = t^2; if t(t-1)/2 < n < t(t+1)/2 then a(n) = t(t-1).
EXAMPLE
a(9) = 12 since spiral is as marked by 9 X's in 4*3 = 12 rectangle:
X.XX
X..X
XXXX
MATHEMATICA
ar[n_]:=Module[{c=(Sqrt[8n+1]-1)/2}, Floor[c]Ceiling[c]]; Array[ar, 70, 0] (* Harvey P. Dale, Feb 27 2012 *)
PROG
(Haskell)
a056942 n = a056942_list !! n
a056942_list = concatMap
(\x -> (x ^ 2) : (take x $ repeat (x * (x + 1)))) [0..]
-- Reinhard Zumkeller, Feb 11 2014
(Python)
from math import isqrt
def A056942(n): return (isqrt(n<<3)+1>>1)*((k:=isqrt(m:=n+1<<1))-((m>=k*(k+1)+1)^1)) # Chai Wah Wu, Jun 10 2025
KEYWORD
easy,nice,nonn
AUTHOR
Henry Bottomley, Jul 13 2000
STATUS
approved