OFFSET
1,1
LINKS
Ray Chandler, Table of n, a(n) for n = 1..1000
FORMULA
a(n)=a(n-1)+10^(n-1)*(8-[a(n-1)/2^(n-1) mod 2]) i.e. a(n) ends with a(n-1); if (n-1)-th term is divisible by 2^n then n-th term begins with an 8, if not then n-th term begins with a 7.
PROG
(PARI) A053379_first(n, t=0)=vector(n, k, t+=(8-(t%2^k>0))*10^(k-1)) \\ M. F. Hasler, Feb 02 2026
CROSSREFS
KEYWORD
base,nonn
AUTHOR
Henry Bottomley, Mar 06 2000
STATUS
approved
