OFFSET
1,1
LINKS
Ray Chandler, Table of n, a(n) for n = 1..1000
FORMULA
a(n)=a(n-1)+10^(n-1)*(8-5*[a(n-1)/2^(n-1) mod 2]) i.e. a(n) ends with a(n-1); if (n-1)-th term is divisible by 2^n then n-th term begins with an 8, if not then n-th term begins with a 3.
MATHEMATICA
Flatten[Table[Select[FromDigits/@Tuples[{3, 8}, n], Divisible[#, 2^n]&], {n, 18}]] (* Harvey P. Dale, Dec 25 2015 *)
CROSSREFS
KEYWORD
base,nonn
AUTHOR
Henry Bottomley, Mar 06 2000
STATUS
approved