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A050922
Triangle in which n-th row gives prime factors of n-th Fermat number 2^(2^n)+1.
11
3, 5, 17, 257, 65537, 641, 6700417, 274177, 67280421310721, 59649589127497217, 5704689200685129054721, 1238926361552897, 93461639715357977769163558199606896584051237541638188580280321
OFFSET
0,1
COMMENTS
Alternatively, list of prime factors of terms of A001317 in order of their first appearance. - Labos Elemer, Jan 21 2002
From T. D. Noe, Jan 29 2009: (Start)
That these two definitions give the same sequence follows from the fact (stated as a formula in A001317) that A001317(n) is the product of Fermat numbers F(i) according to which bits of n are set.
For instance, for n=41, the binary representation of n is 101001, which has bits 0, 3 and 5 set. A001317(n) = 3311419785987 = 3*257*4294967297 = F(0)*F(3)*F(5).
This factorization also explains why the "first 31 numbers give odd-sided constructible polygons". I think Hewgill first noticed this factorization. (End)
REFERENCES
M. Aigner and G. M. Ziegler, Proofs from The Book, Springer-Verlag, Berlin, 2nd. ed., 2001; see p. 3.
EXAMPLE
Triangle begins:
3;
5;
17;
257;
65537;
641, 6700417;
274177, 67280421310721;
59649589127497217, 5704689200685129054721;
1238926361552897, 93461639715357977769163558199606896584051237541638188580280321;
...
A001317(127) = 3*5*17*257*65537.641*6700417*274177*6728042130721, A001317(128) = 59649589127497217*5704689200685129054721. See also A050922. Compare with A053576, where 2 and A000215 appear as prime factors. - Labos Elemer, Jan 21 2002
MATHEMATICA
Flatten[Transpose[FactorInteger[#]][[1]]&/@Table[2^(2^n)+1, {n, 0, 8}]] (* Harvey P. Dale, May 18 2012 *)
PROG
(PARI) for(n=0, 1e3, f=factor(2^(2^n)+1)[, 1]; for(i=1, #f, print1(f[i], ", "))) \\ Felix Fröhlich, Aug 16 2014
KEYWORD
nonn,tabf,nice
AUTHOR
N. J. A. Sloane, Dec 30 1999
EXTENSIONS
More terms from Larry Reeves (larryr(AT)acm.org), Apr 13 2000.
Edited by N. J. A. Sloane, Jan 31 2009 at the suggestion of T. D. Noe
Link to Munafo webpage fixed by Robert Munafo, Dec 09 2009
STATUS
approved