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A045654
Number of 2n-bead balanced binary strings, rotationally equivalent to complement.
10
1, 2, 6, 8, 22, 32, 72, 128, 278, 512, 1056, 2048, 4168, 8192, 16512, 32768, 65814, 131072, 262656, 524288, 1049632, 2097152, 4196352, 8388608, 16781384, 33554432, 67117056, 134217728, 268451968, 536870912, 1073774592, 2147483648
OFFSET
0,2
FORMULA
a(0)=1, a(2n) = a(n)+2^(2n), a(2n+1) = 2^(2n+1). - Ralf Stephan, Jun 07 2003
G.f.: 1/(1-x) + sum(k>=0, t(1+2t-2t^2)/(1-t^2)/(1-2t), t=x^2^k). - Ralf Stephan, Aug 30 2003
For n >= 1, a(n) = sum(0<=k<=A007814(n), 2^(n/2^k)). - David W. Wilson, Jan 01 2012
Inverse Moebius transform of A045663. - Andrew Howroyd, Sep 15 2019
PROG
(PARI) a(n)={if(n==0, 1, my(s=0); while(n%2==0, s+=2^n; n/=2); s + 2^n)} \\ Andrew Howroyd, Sep 22 2019
(Python)
def A045654(n): return sum(1<<(n>>k) for k in range((~n & n-1).bit_length()+1)) if n else 1 # Chai Wah Wu, Jul 22 2024
CROSSREFS
KEYWORD
nonn
STATUS
approved