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A037246
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Total number of fixed points in free homeomorphically irreducible trees with n nodes.
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0
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1, 0, 0, 1, 1, 1, 3, 5, 10, 16, 38, 66, 143, 268, 564, 1100, 2282, 4546, 9382, 18977, 39112, 79891, 164917, 339195, 702041, 1451628, 3013442, 6257561, 13029327, 27152492, 56698062, 118518363, 248137778, 520085704, 1091520783, 2293229235, 4823466463
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OFFSET
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1,7
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LINKS
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FORMULA
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Reference gives a recurrence.
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MAPLE
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Hpj := proc(Hofxy, p, j)
coeftayl(Hofxy, x=0, p) ;
coeftayl(%, y=0, j) ;
simplify(%) ;
end proc:
Hxy := proc(x, y, pmax, hxyinit)
if pmax = 0 then
x*y ;
else
pp := 1;
for p from 1 to pmax do
t :=1 ;
for j from 1 to p do
t := t*(1+x^p*y^j+add(x^(k*p), k=2..pmax+1))^Hpj(hxyinit, p, j) ;
end do:
pp := pp*t ;
end do:
x*y*%/(1+x*y) ;
end if;
end proc:
hxyfin := Hxy(x, y, 0, 0) ;
for pmax from 2 to 40 do
Hxy(x, y, pmax, hxyfin) ;
taylor(%, x=0, pmax+2) ;
convert(%, polynom) ;
taylor(%, y=0, pmax+2) ;
hxyfin := convert(%, polynom) ;
hxy := (1+x*y)*hxyfin+subs({x=x^2, y=1}, hxyfin)*(1-x*y)-hxyfin^2*(1+x*y)/2+subs({x=x^2, y=y^2}, hxyfin)*(x*y-1)/2 ;
for p from 0 to pmax do
ap := 0 ;
for j from 1 to p do
ap := ap+j*Hpj(hxy, p, j) ;
end do:
printf("%d, ", ap) ;
end do:
print() ;
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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