A035017 One quarter of 9-factorial numbers.

1, 13, 286, 8866, 354640, 17377360, 1007886880, 67528420960, 5132159992960, 436233599401600, 41005958343750400, 4223613709406291200, 473044735453504614400, 57238412989874058342400, 7440993688683627584512000, 1034298122727024234247168000, 153076122163599586668580864000

Offset

1,2

Links

G. C. Greubel, Table of n, a(n) for n = 1..325

Index entries for sequences related to factorial numbers.

Formula

4*a(n) = (9*n-5)(!^9) := Product_{j=1..n} (9*j-5).

E.g.f.: (-1+(1-9*x)^(-4/9))/4.

From G. C. Greubel, Oct 18 2022: (Start)

a(n) = (1/4) * 9^n * Pochhammer(n, 4/9).

a(n) = (9*n-5)*a(n-1). (End)

From Amiram Eldar, Dec 21 2022: (Start)

a(n) = A144829(n)/4.

Sum_{n>=1} 1/a(n) = 4*(e/9^5)^(1/9)*(Gamma(4/9) - Gamma(4/9, 1/9)). (End)

Mathematica

s=1; lst={s}; Do[s+=n*s; AppendTo[lst, s], {n, 12, 2*5!, 9}]; lst (* Vladimir Joseph Stephan Orlovsky, Nov 08 2008 *)
Table[9^n*Pochhammer[4/9, n]/4, {n, 40}] (* G. C. Greubel, Oct 18 2022 *)

Prog

(Magma) [n le 1 select 1 else (9*n-5)*Self(n-1): n in [1..40]]; // G. C. Greubel, Oct 18 2022
(SageMath) [9^n*rising_factorial(4/9, n)/4 for n in range(1, 40)] # G. C. Greubel, Oct 18 2022

Crossrefs

Cf. A007559, A034171, A035012, A035013, A035017, A035018.

Cf. A035020, A035021, A035022, A035023, A045756, A144829.

Sequence in context: A160294 A092145 A278628 * A064750 A228753 A249864

Adjacent sequences: A035014 A035015 A035016 * A035018 A035019 A035020

Keyword

easy,nonn

Author

Wolfdieter Lang

Status

approved