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A025446
Number of partitions of n into 2 nonnegative cubes.
7
1, 1, 1, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 1
OFFSET
0,1730
COMMENTS
a(1729) = 2, the first point where a value larger than 1 appears, and where this sequence differs from A373972. - Antti Karttunen, Jun 24 2024
LINKS
FORMULA
a(n) = A010057(n) + A025455(n) = A010057(n) XOR A025455(n). [The latter by Fermat's Last Theorem] - Antti Karttunen, Jun 24 2024
EXAMPLE
From Antti Karttunen, Jun 24 2024: (Start)
8 = 0^3 + 2^3, and as there are no other partitions of 8 into 2 nonnegative cubes, a(8) = 1.
16 = 2^3 + 2^3, and as there are no other partitions of 16 into 2 nonnegative cubes, a(16) = 1.
1729 = 1^3 + 12^3 = 9^3 + 10^3, and as there are no other partitions of 1729 into 2 nonnegative cubes, a(1729) = 2.
(End)
PROG
(PARI) A025446(n) = if(n<=2, 1, my(s=0, x=sqrtnint(n, 3)); forstep(i=x, 0, -1, my(x3=i^3, y3=n-x3); if(y3>x3, return(s), s += ispower(y3, 3)))); \\ Antti Karttunen, Jun 24 2024
CROSSREFS
Cf. A010057, A025455, A004999 (indices of nonzero terms), A373972 (their characteristic function).
Sequence in context: A371690 A179830 A266216 * A373972 A266300 A266605
KEYWORD
nonn
EXTENSIONS
Data section extended up to a(126) and the secondary offset added by Antti Karttunen, Jun 24 2024
STATUS
approved