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A016762 a(n) = (2*n + 1)^10. 3
1, 59049, 9765625, 282475249, 3486784401, 25937424601, 137858491849, 576650390625, 2015993900449, 6131066257801, 16679880978201, 41426511213649, 95367431640625, 205891132094649, 420707233300201, 819628286980801, 1531578985264449, 2758547353515625, 4808584372417849 (list; graph; refs; listen; history; text; internal format)
OFFSET

0,2

LINKS

Vincenzo Librandi, Table of n, a(n) for n = 0..10000

Index entries for linear recurrences with constant coefficients, signature (11,-55,165,-330,462,-462,330,-165,55,-11,1).

FORMULA

a(n) = A016757(n)^2. - Michel Marcus, Dec 27 2016

From G. C. Greubel, Dec 27 2016: (Start)

G.f.: (1 +59038*x +9116141*x^2 +178300904*x^3 +906923282*x^4 + 1527092468*x^5 +906923282*x^6 +178300904*x^7 +9116141*x^8 +59038*x^9 + x^10)/(1-x)^11.

E.g.f.: (1 +59048*x +4823764*x^2 +42225920*x^3 +100635040*x^4 + 93590784*x^5 +40322688*x^6 +8724480*x^7 +963840*x^8 +51200*x^9 + 1024*x^10)*exp(x). (End)

Sum_{n>=0} 1/a(n) = 31*Pi^10/2903040. - Amiram Eldar, Oct 11 2020

MATHEMATICA

(2Range[0, 20]+1)^10 (* Harvey P. Dale, Nov 06 2011 *)

PROG

(MAGMA) [(2*n+1)^10: n in [0..20]]; // Vincenzo Librandi, Sep 07 2011

(PARI) for(n=0, 20, print1((2*n+1)^10, ", ")) \\ G. C. Greubel, Dec 27 2016

CROSSREFS

Cf. A016750, A016757.

Sequence in context: A017501 A017633 A203653 * A305931 A305934 A016774

Adjacent sequences:  A016759 A016760 A016761 * A016763 A016764 A016765

KEYWORD

nonn,easy

AUTHOR

N. J. A. Sloane

STATUS

approved

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Last modified June 26 03:21 EDT 2022. Contains 354871 sequences. (Running on oeis4.)