%I #27 Sep 08 2022 08:44:41
%S 1,59049,9765625,282475249,3486784401,25937424601,137858491849,
%T 576650390625,2015993900449,6131066257801,16679880978201,
%U 41426511213649,95367431640625,205891132094649,420707233300201,819628286980801,1531578985264449,2758547353515625,4808584372417849
%N a(n) = (2*n + 1)^10.
%H Vincenzo Librandi, <a href="/A016762/b016762.txt">Table of n, a(n) for n = 0..10000</a>
%H <a href="/index/Rec#order_11">Index entries for linear recurrences with constant coefficients</a>, signature (11,-55,165,-330,462,-462,330,-165,55,-11,1).
%F a(n) = A016757(n)^2. - _Michel Marcus_, Dec 27 2016
%F From _G. C. Greubel_, Dec 27 2016: (Start)
%F G.f.: (1 +59038*x +9116141*x^2 +178300904*x^3 +906923282*x^4 + 1527092468*x^5 +906923282*x^6 +178300904*x^7 +9116141*x^8 +59038*x^9 + x^10)/(1-x)^11.
%F E.g.f.: (1 +59048*x +4823764*x^2 +42225920*x^3 +100635040*x^4 + 93590784*x^5 +40322688*x^6 +8724480*x^7 +963840*x^8 +51200*x^9 + 1024*x^10)*exp(x). (End)
%F Sum_{n>=0} 1/a(n) = 31*Pi^10/2903040. - _Amiram Eldar_, Oct 11 2020
%t (2Range[0,20]+1)^10 (* _Harvey P. Dale_, Nov 06 2011 *)
%o (Magma) [(2*n+1)^10: n in [0..20]]; // _Vincenzo Librandi_, Sep 07 2011
%o (PARI) for(n=0,20, print1((2*n+1)^10, ", ")) \\ _G. C. Greubel_, Dec 27 2016
%Y Cf. A016750, A016757.
%K nonn,easy
%O 0,2
%A _N. J. A. Sloane_
|