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A014635
a(n) = 2*n*(4*n - 1).
20
0, 6, 28, 66, 120, 190, 276, 378, 496, 630, 780, 946, 1128, 1326, 1540, 1770, 2016, 2278, 2556, 2850, 3160, 3486, 3828, 4186, 4560, 4950, 5356, 5778, 6216, 6670, 7140, 7626, 8128, 8646, 9180, 9730, 10296, 10878, 11476, 12090, 12720, 13366, 14028, 14706
OFFSET
0,2
COMMENTS
Even hexagonal numbers.
Number of edges in the join of two complete graphs of order 3n and n, K_3n * K_n - Roberto E. Martinez II, Jan 07 2002
Bisection of A000384. Also, this sequence arises from reading the line from 0, in the direction 0, 6, ..., in the square spiral whose vertices are the triangular numbers A000217. Perfect numbers are members of this sequence because a(A134708(n)) = A000396(n). Also, positive members are a bisection of A139596. - Omar E. Pol, May 07 2008
FORMULA
a(n) = C(4*n,2), n>=0. - Zerinvary Lajos, Jan 02 2007
O.g.f.: 2*x*(3+5*x)/(1-x)^3. - R. J. Mathar, May 06 2008
a(n) = 8*n^2 - 2*n. - Omar E. Pol, May 07 2008
a(n) = a(n-1) + 16*n - 10 (with a(0)=0). - Vincenzo Librandi, Nov 20 2010
E.g.f.: (8*x^2 + 6*x)*exp(x). - G. C. Greubel, Jul 18 2017
From Vaclav Kotesovec, Aug 18 2018: (Start)
Sum_{n>=1} 1/a(n) = 3*log(2)/2 - Pi/4.
Sum_{n>=1} (-1)^n / a(n) = log(2)/2 + log(1+sqrt(2))/sqrt(2) - Pi / 2^(3/2). (End)
a(n) = A154105(n-1) - A016754(n-1). - Leo Tavares, May 02 2023
MAPLE
[seq(binomial(4*n, 2), n=0..43)]; # Zerinvary Lajos, Jan 02 2007
MATHEMATICA
s=0; lst={s}; Do[s+=n++ +6; AppendTo[lst, s], {n, 0, 7!, 16}]; lst (* Vladimir Joseph Stephan Orlovsky, Nov 16 2008 *)
Table[2*n*(4*n - 1), {n, 0, 50}] (* G. C. Greubel, Jul 18 2017 *)
PolygonalNumber[6, Range[0, 90, 2]] (* or *) LinearRecurrence[{3, -3, 1}, {0, 6, 28}, 50] (* Harvey P. Dale, Jan 21 2023 *)
PROG
(Magma) [2*n*(4*n-1): n in [0..50]]; // Vincenzo Librandi, Apr 25 2011
(PARI) a(n)=2*n*(4*n-1) \\ Charles R Greathouse IV, Jun 17 2017
CROSSREFS
KEYWORD
nonn,easy
EXTENSIONS
More terms from Erich Friedman
STATUS
approved