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A005536 a(0) = 0; thereafter a(2n) = n - a(n) - a(n-1), a(2n+1) = n - 2a(n) + 1.
(Formerly M2274)
6
0, 1, 0, 0, 1, 3, 3, 4, 3, 3, 1, 0, 0, 1, 0, 0, 1, 3, 3, 4, 6, 9, 10, 12, 12, 13, 12, 12, 13, 15, 15, 16, 15, 15, 13, 12, 12, 13, 12, 12, 10, 9, 6, 4, 3, 3, 1, 0, 0, 1, 0, 0, 1, 3, 3, 4, 3, 3, 1, 0, 0, 1, 0, 0, 1, 3, 3, 4, 6, 9, 10, 12, 12, 13, 12, 12, 13, 15, 15, 16, 18, 21, 22, 24, 27, 31, 33 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,6
COMMENTS
A "Von Koch" sequence generated by the first Feigenbaum symbolic sequence.
REFERENCES
N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
R. G. Stanton, W. L. Kocay and P. H. Dirksen, Computation of a combinatorial function, pp. 569-578 of C. J. Nash-Williams and J. Sheehan, editors, Proceedings of the Fifth British Combinatorial Conference 1975. Utilitas Math., Winnipeg, 1976.
LINKS
J.-P. Allouche and J. Shallit, The Ring of k-regular Sequences, II, Theoret. Computer Sci., 307 (2003), 3-29.
Hsien-Kuei Hwang, S. Janson, and T.-H. Tsai, Exact and Asymptotic Solutions of a Divide-and-Conquer Recurrence Dividing at Half: Theory and Applications, ACM Transactions on Algorithms, 13:4 (2017), #47; DOI: 10.1145/3127585.
Hsien-Kuei Hwang, Svante Janson, and Tsung-Hsi Tsai, Identities and periodic oscillations of divide-and-conquer recurrences splitting at half, arXiv:2210.10968 [cs.DS], 2022, p. 44 and 49.
FORMULA
Partial sums of A065359. a(n) = Sum_{i=0..n} Sum_{k=0..i} (-1)^k*(floor(i/2^k) - 2*floor(i/2^(k+1))). - Benoit Cloitre, Mar 28 2004
G.f.: (1/(1-x)^2) * Sum_{k>=0} (-1)^k*x^2^k/(1 + x^2^k). - Ralf Stephan, Apr 27 2003
a(n) = -n*(n-2) + 3*Sum_{k=1..n-1} Sum_{i=1..k} A035263(i+1), where A035263 is the first Feigenbaum symbolic sequence. - Benoit Cloitre, May 29 2003
MATHEMATICA
a[n_] := a[n] = If[n == 0, 0, hn = Floor[n/2]; If[OddQ[n], hn - 2 a[hn] + 1, hn - a[hn] - a[hn - 1]]]; t = Table[a[n], {n, 0, 100}] (* T. D. Noe, Mar 22 2012 *)
PROG
(PARI) a(n)=-n*(n-2)+3*sum(k=1, n-1, sum(i=1, k, abs(subst(Pol(binary(i+1))- Pol(binary(i)), x, 1)%2))) \\ Benoit Cloitre, May 29 2003
(PARI) a(n)=polcoeff(1/(1-x)^2*sum(k=0, 10, (-1)^k*x^2^k/(1+x^2^k)) +O(x^(n+1)), n)
CROSSREFS
Sequence in context: A239207 A329157 A082978 * A172515 A188590 A080038
KEYWORD
nonn,look
AUTHOR
EXTENSIONS
More terms and better description from Ralf Stephan, Sep 13 2003
a(0)=0 added to data and offset changed by N. J. A. Sloane, Jun 16 2021 at the suggestion of Georg Fischer.
STATUS
approved

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Last modified April 19 19:02 EDT 2024. Contains 371798 sequences. (Running on oeis4.)