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 A004782 Numbers k such that 2*(2k-3)!/(k!*(k-1)!) is an integer. 5
 2, 3, 7, 16, 21, 29, 43, 46, 67, 78, 89, 92, 105, 111, 127, 141, 154, 157, 171, 188, 191, 205, 210, 211, 221, 229, 232, 239, 241, 267, 277, 300, 309, 313, 316, 323, 326, 331, 346, 369, 379, 415, 421, 430, 436, 441, 443, 451, 460, 461, 465, 469, 477 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,1 COMMENTS Superset of A081767, as proved by Luke Pebody. Terms not in A081767 include 3, 7, 127, 511, ... - Ralf Stephan, Oct 12 2004 See A260642 for A004782 \ A081767. - M. F. Hasler, Nov 11 2015 Equivalently, numbers k such that binomial(2k-3,k-1) == 0 (mod k*(k-1)/2), or: binomial(2k-2,k-1) == 0 (mod k^2-k), or: the Catalan number A000108(k-1) is divisible by k-1, i.e., a(n) = A014847(n) + 1. Indeed, 2(2k-3)!/(k!*(k-1)!) = 2(2k-2)!/(k!(k-1)!(2k-2)) = C(k-1)/(k-1). - M. F. Hasler, Nov 11 2015 LINKS Vincenzo Librandi, Table of n, a(n) for n = 1..1000 FORMULA a(n) = A014847(n) + 1. - Enrique Pérez Herrero, Feb 03 2013 MATHEMATICA Select[Range[500], IntegerQ[2 (2 # - 3)!/(#! (# - 1)!)] &] (* Arkadiusz Wesolowski, Sep 06 2011 *) PROG (PARI) for(n=2, 999, binomial(2*n-2, n-1)%(n^2-n)||print1(n", ")) (PARI) is_A004782(n)=!binomod(2*n-2, n-1, n^2-n) \\ Using http://home.gwu.edu/~maxal/gpscripts/binomod.gp by M. Alekseyev. - M. F. Hasler, Nov 11 2015 CROSSREFS Sequence in context: A058698 A058699 A250193 * A049956 A289844 A153056 Adjacent sequences: A004779 A004780 A004781 * A004783 A004784 A004785 KEYWORD nonn AUTHOR R. K. Guy EXTENSIONS Offset corrected and initial term added by Arkadiusz Wesolowski, Sep 06 2011 STATUS approved

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Last modified April 16 17:08 EDT 2024. Contains 371749 sequences. (Running on oeis4.)