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A078987
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Chebyshev U(n,x) polynomial evaluated at x=19.
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10
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1, 38, 1443, 54796, 2080805, 79015794, 3000519367, 113940720152, 4326746846409, 164302439443390, 6239165952002411, 236924003736648228, 8996872976040630253, 341644249085807301386, 12973484592284636822415, 492650770257730391950384, 18707755785201470257292177
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OFFSET
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0,2
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COMMENTS
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A078986(n+1)^2 - 10*(6*a(n))^2 = +1, n>=0 (Pell equation +1, see A033313 and A033317).
a(n) equals the number of 01-avoiding words of length n on alphabet {0,1,...,37}. - Milan Janjic, Jan 26 2015
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LINKS
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Colin Barker, Table of n, a(n) for n = 0..632
R. Flórez, R. A. Higuita, A. Mukherjee, Alternating Sums in the Hosoya Polynomial Triangle, Article 14.9.5 Journal of Integer Sequences, Vol. 17 (2014).
Tanya Khovanova, Recursive Sequences
Index entries for sequences related to Chebyshev polynomials.
Index entries for linear recurrences with constant coefficients, signature (38,-1).
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FORMULA
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a(n) = 38*a(n-1) - a(n-2), n>=1, a(-1)=0, a(0)=1.
a(n) = S(n, 38) with S(n, x) = U(n, x/2), Chebyshev's polynomials of the second kind. See A049310.
G.f.: 1/(1-38*x+x^2).
a(n) = Sum_{k=0..floor(n/2)} (-1)^k*binomial(n-k, k)*38^(n-2*k).
a(n) = ((19+6*sqrt(10))^(n+1) - (19-6*sqrt(10))^(n+1))/(12*sqrt(10)).
a(n) = Sum_{k=0..n} A101950(n,k)*37^k. - Philippe Deléham, Feb 10 2012
Product_{n>=0} (1 + 1/a(n)) = 1/3*(3 + sqrt(10)). - Peter Bala, Dec 23 2012
Product_{n>=1} (1 - 1/a(n)) = 3/19*(3 + sqrt(10)). - Peter Bala, Dec 23 2012
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MATHEMATICA
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lst={}; Do[AppendTo[lst, GegenbauerC[n, 1, 19]], {n, 0, 8^2}]; lst (* Vladimir Joseph Stephan Orlovsky, Sep 11 2008 *)
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PROG
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(Sage) [lucas_number1(n, 38, 1) for n in xrange(1, 16)] # Zerinvary Lajos, Nov 07 2009
(PARI) a(n)=subst(polchebyshev(n, 2), x, 19) \\ Charles R Greathouse IV, Feb 10 2012
(PARI) Vec(1/(1-38*x+x^2) + O(x^50)) \\ Colin Barker, Jun 15 2015
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CROSSREFS
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Sequence in context: A218740 A158702 A239364 * A009982 A041685 A221385
Adjacent sequences: A078984 A078985 A078986 * A078988 A078989 A078990
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KEYWORD
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nonn,easy
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AUTHOR
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Wolfdieter Lang, Jan 10 2003
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STATUS
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approved
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