OFFSET
1,2
COMMENTS
After a(1) = 1 when determining the next term in the sequence one must not only ensure that it contains no 1 bits that are a knight's move apart from any previous 1 bit, including the earlier 1 bits in the term itself, but also that the next square after the end of the term is not a knight's move apart from any previous 1 bit as the next term must begin with a 1 bit.
It is conjectured that the sequence contains all positive integers.
LINKS
Scott R. Shannon, Table of n, a(n) for n = 1..1000
Scott R. Shannon, Image of the first 1000 terms on the square spiral. The 1 bits are black while the 0 bits are light gray. The bits that comprise each term are connected by a red line.
EXAMPLE
The spiral begins:
.
.
1---0---0---0---0---1---1 1
| | |
0 0---0---0---0---0 1 0
| | | | |
0 0 0---1---0 0 0 0
| | | | | | |
1 0 0 1---1 0 1 0
| | | | | |
0 0 0---1---0---0 0 0
| | | |
1 0---0---0---0---0---1 0
| |
1---1---0---1---0---0---1---1
.
a(1) = 1 by definition.
a(2) = 2 as the 2nd square is not a knight's move away from the 1st square that contains a 1 bit, while the 4th square, the next square after the end of a(2) = 2, can contain a 1 bit as it is not a knight's move away from any existing 1 bit.
a(4) = 131072. This term must be 3 or more but it cannot end on the 9th, 10th, 11th, ... 23rd, 24th square as the next square to all of these is a knight's move away from a square containing a 1 bit. This leaves the 25th square are the earliest square a(4) can end on as the 26th square can contain a 1 bit as it is not a knight's move away from any other square containing a 1 bit. This leaves 131072 = 2^17 as the first number satisfying these conditions.
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Scott R. Shannon, May 30 2026
STATUS
approved
