login
A395457
Triangle read by rows: T(n,k) = (1/(2k)!) * Sum_{j=0..2k} (-1)^j * binomial(2k,j) * (3+k-j)^(2n).
8
1, 9, 1, 81, 55, 1, 729, 1351, 140, 1, 6561, 26335, 6951, 266, 1, 59049, 465751, 246730, 22827, 435, 1, 531441, 7859215, 7508501, 1323652, 58542, 649, 1, 4782969, 129442951, 210766920, 63436373, 5146570, 128128, 910, 1, 43046721, 2104469695, 5652751651, 2734926558, 364558623, 16169582, 250978, 1220, 1
OFFSET
0,2
REFERENCES
P. L. Butzer, K. Schmidt, E. L. Stark, and L. Vogt, Central factorial numbers; their main properties and some applications. Numerical Functional Analysis and Optimization, 10(5-6), (1989), 419-488.
J. Riordan, Combinatorial identities (Vol. 217), Wiley, New York, 1968.
FORMULA
Let F(t, n, k) be generalized central factorial numbers of the second kind: F(t,n,k) = (1/(2k)!) * Sum_{j=0..2k} (-1)^j * binomial(2k,j) * (t+k-j)^(2n), then:
F(0,n,k) = A387597(n,k)/k! = A269945(n,k);
F(1,n,k) = A392337(n,k)/k! = A394692(n,k);
F(2,n,k) = A390029(n,k)/k! = A395456(n,k);
F(3,n,k) = T(n,k) (this sequence).
G.f. for T(n,k) is centered Newton's polynomial for f(s) = s^(2n): s^(2n) = Sum_{k=0..2n} T(2n,k) (s-3)^[k], where (s-3)^[k] are central factorials.
EXAMPLE
Triangle begins:
k= 0 1 2 3 4 5 6
----------------------------------------------------------------
n=0: 1;
n=1: 9, 1;
n=2: 81, 55, 1;
n=3: 729, 1351, 140, 1;
n=4: 6561, 26335, 6951, 266, 1;
n=5: 59049, 465751, 246730, 22827, 435, 1;
n=6: 531441, 7859215, 7508501, 1323652, 58542, 649, 1;
...
MATHEMATICA
T[t_, n_, k_] := 1/ k!* Sum[(-1)^j * Binomial[k, j] * (t + k/2 - j)^n, {j, 0, k}]; Column[Table[T[3, 2 n, 2 k], {n, 0, 10}, {k, 0, n}]]
KEYWORD
nonn,easy,tabl,changed
AUTHOR
Petro Kolosov, Apr 23 2026
STATUS
approved