OFFSET
1,1
COMMENTS
Smallest a(n) with omega(a(n)) = m is a(n) = A002110(m), since prime(m) < 2^m for m > 1.
There are a finite number of k with 1 < omega(k) = m such that p | k for any given least prime factor p. For k with omega(k) = 2 (i.e., for k in A138109), there are pi(prime(i)^2) - i = A079047(i) numbers k with lpf(k) = prime(i).
This sequence includes A384000(n) for n > 1.
LINKS
Michael De Vlieger, Table of n, a(n) for n = 1..10000
EXAMPLE
Table of n, a(n) for select n:
n a(n)
---------------------------------------------
1 6 = 2 * 3
2 15 = 3 * 5
3 21 = 3 * 7
4 30 = 2 * 3 * 5
5 35 = 5 * 7
6 42 = 2 * 3 * 7
25 210 = 2 * 3 * 5 * 7
114 1001 = 7 * 11 * 13
253 2310 = 2 * 3 * 5 * 7 * 11
3281 30030 = 2 * 3 * 5 * 7 * 11 * 13
27220 268801 = 13 * 23 * 29 * 31
51003 510510 = 2 * 3 * 5 * 7 * 11 * 13 * 17
MATHEMATICA
s = Select[Range[500], 1 < PrimeNu[#] == PrimeOmega[#] &]; Select[s, Function[{p, q, k}, q < p^k] @@ {First[#], Last[#], Length[#]} &[FactorInteger[#][[;; , 1]] ] &]
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Michael De Vlieger, Apr 18 2026
STATUS
approved
