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A330205
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Composite numbers k such that P(k, 7) == 7 (mod k), where P(k, 7) = A084768(k) is the k-th Legendre polynomial evaluated at 7.
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0
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6, 15, 21, 22, 105, 119, 231, 426, 483, 1290, 1939, 4429, 4450, 4578, 10609, 12999, 14118, 16899, 23262, 26733, 37401, 39858, 82194, 108345, 121335, 127434, 302253, 380757, 724647, 836437, 840147, 1078270, 1522677, 2007411, 15009050, 28913991
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OFFSET
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1,1
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COMMENTS
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P(p, 7) == 7 (mod p) for all primes p. This is a special case of Schur congruences (see A330203 for references). This sequence consists of the composite numbers for which the congruence holds.
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LINKS
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EXAMPLE
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6 is in the sequence since it is composite and P(6, 7) = 1651609 == 7 (mod 6).
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MATHEMATICA
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Select[Range[2000], CompositeQ[#] && Divisible[LegendreP[#, 7] - 7, #] &]
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PROG
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(PARI) isok(k) = Mod(subst(pollegendre(k), x, 7), k) == 7;
forcomposite (k=1, 10000, if (isok(k), print1(k, ", "))); \\ Michel Marcus, Dec 06 2019
(Sage)
a, b = 1, 7
for n in range(2, 10000):
a, b = b, ((14*n-7)*b - (n-1)*a)//n
if (b%n == 7%n) and (not Integer(n).is_prime()): print(n) # Robin Visser, Aug 18 2023
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CROSSREFS
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KEYWORD
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nonn,more
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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