OFFSET
1,2
COMMENTS
The length of a chain is the number of relations, so chains of length 0 are just single partitions of n.
LINKS
John Tyler Rascoe, Python code.
EXAMPLE
Triangle begins:
k= 0 1 2 3 4 5 6 7 8 9
n= 1 [1]
n= 2 [2, 2]
n= 3 [3, 7, 4]
n= 4 [5, 20, 25, 10]
n= 5 [7, 44, 93, 82, 26]
n= 6 [11, 98, 303, 432, 292, 76]
n= 7 [15, 189, 821, 1711, 1872, 1040, 232]
n= 8 [22, 369, 2125, 6005, 9389, 8314, 3916, 764]
n= 9 [30, 670, 5024, 18590, 39086, 49158, 36728, 15070, 2620]
n=10 [42, 1212, 11521, 54085, 146473, 244889, 257636, 166546, 60556, 9496]
...
The chain of partitions (2)<(21)<(211)<(421) has length 3 and the last element is a partition of 7 so it is counted under T(7,3) = 1711.
T(3,1) = 7 counts: (1)<(111), (11)<(111), (1)<(21), (2)<(21), (11)<(21), (1)<(3), (2)<(3).
PROG
(Python) # see links
CROSSREFS
KEYWORD
nonn,tabl
AUTHOR
John Tyler Rascoe, Feb 10 2026
STATUS
approved
