login
A392870
Multiplicative inverse of {n mod A117366(n)} in finite field F(A117366(n)), where A117366 gives the smallest prime greater than the largest prime dividing n.
4
1, 2, 2, 1, 3, 1, 8, 2, 4, 5, 6, 3, 4, 4, 1, 1, 9, 2, 17, 6, 10, 3, 24, 4, 2, 2, 3, 2, 15, 4, 6, 2, 2, 14, 6, 1, 10, 20, 7, 3, 21, 5, 35, 8, 5, 12, 44, 2, 9, 1, 3, 1, 49, 4, 9, 1, 21, 23, 30, 2, 11, 3, 7, 1, 11, 1, 53, 7, 8, 3, 36, 3, 13, 5, 3, 10, 12, 12, 62, 5, 1, 32, 74, 8, 17, 41, 5, 4, 12, 6, 3, 6, 2, 22, 8
OFFSET
1,2
LINKS
EXAMPLE
For n = 5, itself a prime, the next larger prime is 7, so 5 mod 7 = 5, whose inverse in F(7) is 3 as 3*5 = 15 == 1 (mod 7), thus a(5) = 3.
For n = 14 = 2*7, the next larger prime is 11, so 14 mod 11 = 3, whose inverse in F(11) is 4, as 3*4 = 12 == 1 (mod 11), thus a(14) = 4.
For n = 15 = 3*5, the next larger prime is 7, so 15 mod 7 = 1, whose inverse in F(11) (like in any field) is 1, thus a(15) = 1.
PROG
(PARI)
A006530(n) = if(n>1, vecmax(factor(n)[, 1]), 1);
A392870(n) = lift(Mod(1/n, nextprime(1+A006530(n))));
CROSSREFS
Cf. A006530, A069830 [= a(prime(n))], A117366, A392865 (multiplicative inverses), A392871 (positions of 1's).
Sequence in context: A069004 A381495 A182490 * A053274 A243926 A281013
KEYWORD
nonn,easy
AUTHOR
Antti Karttunen, Jan 27 2026
STATUS
approved