OFFSET
1,1
COMMENTS
For all n, a(n), a(n)+4, a(n)+8, a(n)+12, a(n)+16, a(n)+20, a(n)+24, a(n)+28 are semiprimes.
No such 9-tuple; i.e., semiprimes from x to x+32, exists.
FORMULA
a(n) == 1 (mod 6).
MAPLE
N:= 6*10^7: # for terms <= N
P:= select(isprime, [seq(i, i=3..(N+28)/3, 2)]):
S:= {}:
for i from 1 do
p:= P[i]; m:= (N+28)/p; if m < p then break fi;
j:= ListTools:-BinaryPlace(P, m);
S:= S union convert(map(`*`, P[i..min(j+1, nP)], p), set)
od:
S2:= S intersect map(`-`, S, 4):
S4:= S2 intersect map(`-`, S2, 8):
S8:= S4 intersect map(`-`, S4, 16):
sort(convert(S8, list)); # Robert Israel, Nov 23 2025
MATHEMATICA
okQ[k_]:=AllTrue[Range[k, k+28, 4], PrimeOmega[#]==2&]; Select[Range[10^6], okQ] (* James C. McMahon, Nov 28 2025 *)
PROG
(PARI) is_a390829(n) = forstep(k=n, n+28, 4, if(bigomega(k)!=2, return(0))); 1 \\ Hugo Pfoertner, Nov 23 2025
CROSSREFS
KEYWORD
nonn
AUTHOR
Soko Kosaka, Nov 21 2025
STATUS
approved
