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A389201
a(n) = A351569(A228058(n)), where A351569(x) is the sum of divisors of the largest unitary divisor of x that is an exponentially odd number, and A228058 gives the numbers satisfying Euler's condition for odd perfect numbers.
4
6, 14, 18, 6, 30, 14, 38, 42, 6, 18, 54, 62, 6, 14, 74, 30, 90, 18, 6, 98, 102, 38, 110, 114, 42, 14, 138, 54, 150, 18, 158, 30, 6, 62, 174, 14, 182, 194, 198, 6, 38, 74, 42, 18, 230, 234, 242, 6, 90, 258, 30, 270, 98, 278, 102, 282, 54, 294, 6, 110, 314, 114, 318, 18, 14, 62, 38, 338, 350, 354, 42, 374, 138, 390, 30
OFFSET
1,1
COMMENTS
For all odd numbers of the form p^(1+4k) * r^2, where p is prime of the form 1+4m (so called "special prime"), k >= 0, r > 1, and gcd(p,r) = 1, a(n) = sigma(p^(1+4k)) = ((p^(2+4k)) - 1) / (p - 1).
FORMULA
a(n) = A000203(A389161(n)) = A351569(A228058(n)).
a(n) = A389203(n) / A389200(n).
EXAMPLE
A228058(520) = 28125 = 3^2 * 5^5, and the largest exponentially odd unitary divisor is 5^5 (its special factor), and sigma(5^5) = ((5^(1+5))-1) / (5-1) = 3906, therefore a(520) = 3906.
PROG
(PARI)
up_to = 20000;
isA228058(n) = if(!(n%2)||(omega(n)<2), 0, my(f=factor(n), y=0); for(i=1, #f~, if(1==(f[i, 2]%4), if((1==y)||(1!=(f[i, 1]%4)), return(0), y=1), if(f[i, 2]%2, return(0)))); (y));
A228058list(up_to) = { my(v=vector(up_to), k=0, n=0); while(k<up_to, n++; if(isA228058(n), k++; v[k] = n)); (v); };
v228058 = A228058list(up_to);
A228058(n) = v228058[n];
A350389(n) = { my(m=1, f=factor(n)); for(k=1, #f~, if(1==(f[k, 2]%2), m *= (f[k, 1]^f[k, 2]))); (m); };
A351569(n) = sigma(A350389(n));
CROSSREFS
KEYWORD
nonn
AUTHOR
Antti Karttunen, Sep 28 2025
STATUS
approved