OFFSET
1,1
COMMENTS
Numbers > 1 not of the form floor(3*k^2/5).
FORMULA
a(n) = n+m+1 if n+m>=floor(3*(m+1)^2/5) and a(n) = n+m otherwise where m = floor(sqrt(5*n/3)).
MATHEMATICA
m[n_]:=Floor[Sqrt[5n/3]]; a[n_]:=If[n+m[n]>=Floor[3(m[n]+1)^2/5], n+m[n]+1, n+m[n]]; Array[a, 67] (* James C. McMahon, Aug 06 2025 *)
PROG
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Chai Wah Wu, Aug 04 2025
STATUS
approved
