OFFSET
1,1
COMMENTS
The numbers x, y and z form a sigma-cubic triple. See Dimitrov link.
If sigma(x)^3 = x^3 + y^3 + z^3 then sigma(x)^3 - x^3 = y^3 + z^3 = (y + z)*(y^2 - y*z + z^2) which enables comparing pairwise divisors of sigma(x)^3 - x^3 to see if sigma(x)^3 - x^3 is the sum of two cubes. - David A. Corneth, Jun 26 2025
LINKS
David A. Corneth, PARI program
S. I. Dimitrov, Generalizations of amicable numbers, arXiv:2408.07387 [math.NT], 2024.
EXAMPLE
(3, 4, 5) is such a triple because sigma(5)^3 = 6^3 = 5^3 + 4^3 + 3^3.
6 is in the sequence as sigma(6)^3 = 6^3 + 8^3 + 10^3. - David A. Corneth, Jun 26 2025
PROG
(PARI) \\ See Corneth link
CROSSREFS
KEYWORD
nonn
AUTHOR
S. I. Dimitrov, Jun 25 2025
EXTENSIONS
Data corrected by David A. Corneth, Jun 26 2025
STATUS
approved
