OFFSET
2,1
COMMENTS
Since a(28) = A376446(700001) = 9317, the present sequence has at least 28 terms.
If we merge A376446(n) and A377124(n*10), taking A376446(n) if and only if n is not a multiple of 10 and A376446(n*10) otherwise, we should get the sequence: 8, 64, 2486, 5, 4268, 8426, 2, 1, 4, 4862, 46, 82, 6248, 6, 6842, 8624, 2684, 28, 9, 7139, 3179, 19, 1397, 1793, 91, 3971, 7931, 9713, 9317 (which the author conjectures to be complete, as the present one).
LINKS
Marco Ripà, Graham's number stable digits: an exact solution, arXiv:2411.00015 [math.GM], 2024.
Wikipedia, Graham's Number.
Wikipedia, Tetration.
FORMULA
a(1) = 8, a(2) = 64, ..., a(28) = 9317 (and a(28) is the last term of the present sequence - conjectured).
CROSSREFS
KEYWORD
nonn,fini,more,new
AUTHOR
Marco Ripà, Nov 25 2024
STATUS
approved