OFFSET
2,1
COMMENTS
Up to a(12) all terms have prime factors whose concatenation length in base n is n, the minimum possible value. Is this true for all a(n)?
a(13) <= 31771759110 = 2*3*5*7*13*61*190787 whose prime factors in base 13 are: 2, 3, 5, 7, 10, 49, 68abc. Sequence is a subsequence of A058760. - Chai Wah Wu, Apr 28 2024
From Chai Wah Wu, Apr 29 2024: (Start)
a(14) <= 1138370792790 = 2*3*5*7*11*877*561917 whose prime factors in base 14 are: 2, 3, 5, 7, b, 469, 108acd.
a(15) <= 23608327052310 = 2*3*5*7*11*13*233*3374069 whose prime factors in base 15 are: 2, 3, 5, 7, b, d, 108, 469ace. (End)
a(14) <= 774841780230, a(15) <= 11924858870610, a(16) <= 256023548755170, a(17) <= 4286558044897590. - Daniel Suteu, Apr 30 2024
For n <= 36, all terms have prime factors whose concatenation length in base n is n, the minimum possible value. - Dominic McCarty, Jan 07 2025
LINKS
Dominic McCarty, Numbers Whose Prime Factorizations Have Every Digit (OEIS A372309), YouTube video (2024).
Dominic McCarty, Java program for A372309
Dominic McCarty, Bounds on a(n) for n <= 36
FORMULA
a(n) >= n!. - Michael S. Branicky, Apr 28 2024
a(n) <= A185122(n). - Michael S. Branicky, Apr 28 2024
EXAMPLE
The factorizations to a(12) are:
a(2) = 2 = 10_2, which contains all digits 0..1.
a(3) = 6 = 2 * 3 = 2_3 * 10_3, which contain all digits 0..2.
a(4) = 38 = 2 * 19 = 2_4 * 103_4, which contain all digits 0..3.
a(5) = 174 = 2 * 3 * 29 = 2_5 * 3_5 * 104_5, which contain all digits 0..4.
a(6) = 2866 = 2 * 1433 = 2_6 * 10345_6, which contain all digits 0..5.
a(7) = 11670 = 2 * 3 * 5 * 389 = 2_7 * 3_7 * 5_7 * 1064_7, which contain all digits 0..6.
a(8) = 135570 = 2 * 3 * 5 * 4519 = 2_8 * 3_8 * 5_8 * 10647_8, which contain all digits 0..7.
a(9) = 1335534 = 2 * 3 * 41 * 61 * 89 = 2_9 * 3_9 * 45_9 * 67_9 * 108_9, which contain all digits 0..8.
a(10) = 15618090 = 2 * 3 * 5 * 487 * 1069, which contain all digits 0..9. See A058909.
a(11) = 155077890 = 2 * 3 * 5 * 11 * 571 * 823 = 2_11 * 3_11 * 5_11 * 10_11 * 47a_11 * 689_11, which contain all digits 0..a.
a(12) = 5148702870 = 2 * 3 * 5 * 151 * 1136579 = 2_12 * 3_12 * 5_12 * 107_12 * 4698ab_12, which contain all digits 0..b.
PROG
(Python)
from math import factorial
from itertools import count
from sympy import factorint
from sympy.ntheory import digits
def a(n):
for k in count(factorial(n)):
s = set()
for p in factorint(k): s.update(digits(p, n)[1:])
if len(s) == n: return k
print([a(n) for n in range(2, 10)]) # Michael S. Branicky, Apr 28 2024
CROSSREFS
KEYWORD
nonn,base,more
AUTHOR
Scott R. Shannon, Apr 26 2024
EXTENSIONS
a(13)-a(16) from Martin Ehrenstein, May 03 2024
a(17) from Dominic McCarty, Jan 07 2025
STATUS
approved