OFFSET
0,3
COMMENTS
a(n)^(1/n^2) tends to 2^(1/4). - Vaclav Kotesovec, Feb 19 2024
LINKS
Paul D. Hanna, Table of n, a(n) for n = 0..120
FORMULA
EXAMPLE
G.f.: A(x) = 1 + x + 2*x^2 + 6*x^3 + 24*x^4 + 134*x^5 + 1054*x^6 + 11848*x^7 + 188498*x^8 + 4229252*x^9 + 132827660*x^10 + 5831280558*x^11 + 357547362450*x^12 +...
log(A(x)) = x + 3*x^2/2 + 13*x^3/3 + 71*x^4/4 + 531*x^5/5 + 5367*x^6/6 + 74313*x^7/7 + 1401295*x^8/8 + 36221143*x^9/9 + 1283583423*x^10/10 + ...
The logarithm of g.f. A(x) equals the series:
log(A(x)) = Sum_{n>=1} (x + 2^n*x^2 + 3^n*x^3 +...+ k^n*x^k +...)^n * (1-x)^n/n,
or,
log(A(x)) = (x + 2*x^2 + 3*x^3 + 4*x^4 + 5*x^5 +...)*(1-x) +
(x + 2^2*x^2 + 3^2*x^3 + 4^2*x^4 + 5^2*x^5 +...)^2 * (1-x)^2/2 +
(x + 2^3*x^2 + 3^3*x^3 + 4^3*x^4 + 5^3*x^5 +...)^3 * (1-x)^3/3 +
(x + 2^4*x^2 + 3^4*x^3 + 4^4*x^4 + 5^4*x^5 +...)^4 * (1-x)^4/4 + ...
This logarithmic series can be written using the Eulerian numbers like so:
log(A(x)) = x/(1-x) + (x + x^2)^2/(1-x)^4/2 + (x + 4*x^2 + x^3)^3/(1-x)^9/3 + (x + 11*x^2 + 11*x^3 + x^4)^4/(1-x)^16/4 + (x + 26*x^2 + 66*x^3 + 26*x^4 + x^5)^5/(1-x)^25/5 + (x + 57*x^2 + 302*x^3 + 302*x^4 + 57*x^5 + x^6)^6/(1-x)^36/6 + ...
+ [ Sum_{k=1..n} A008292(n,k) * x^k ]^n / (1-x)^(n^2)/n +...
PROG
CROSSREFS
KEYWORD
nonn
AUTHOR
Paul D. Hanna, Feb 14 2024
STATUS
approved