|
|
A369771
|
|
Number of the rightmost decimal digits of n^(n^n) that are the same as those of n^(n^(n^n)).
|
|
4
|
|
|
1, 0, 1, 1, 2, 2, 8, 4, 4, 2, 3, 10000000000, 4, 2, 3, 2, 13, 4, 3, 2, 3, 104857600000000000000000000, 4, 1, 2, 4, 12, 8, 2, 2, 3, 205891132094649000000000000000000000000000000, 4, 4, 3, 2, 7, 4, 3, 1, 3, 12089258196146291747061760000000000000000000000000000000000000000
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
-1,5
|
|
COMMENTS
|
The common digits might include leading 0's (such as at n = 5) and they are included in the total.
Let c be a positive integer and assume that k is a positive integer that is not a multiple of 10. If n = k*10^c, then a(n) = c*(n^n) which is all the rightmost 0's of n^(n^n).
|
|
LINKS
|
|
|
FORMULA
|
For any n >=2, a(n) is such that n^(n^n) == n^(n^(n^n)) (mod 10^(a(n))) and n^(n^n) <> n^(n^(n^n)) (mod 10^(a(n)+1)).
|
|
EXAMPLE
|
a(-1) = 1 since (-1)^(-1) = -1 (which is a one-digit number);
a(0) = 0 since 0^0 = 1 so that 0^(0^0) = 0 and 0^(0^(0^0)) = 1 have no digits in common.
For n=5, a(n)=8 since 5^(5^5) == 908203125 (mod 10^9) while 5^(5^(5^5)) == 408203125 (mod 10^9).
|
|
CROSSREFS
|
|
|
KEYWORD
|
sign,base
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|