OFFSET
0,2
COMMENTS
This sequence counts dissections of a convex 4n+4-sided polygon into one square and n hexagons, modulo a simple equivalence relation. The equivalence relation is not defined by a group, but by local moves. Consider the octagon formed by a hexagon adjacent to the square. The local move is half-rotation of such octagons.
It seems that a(n) is divisible by n+1.
FORMULA
a(n) = binomial(5*n+2,n)*(n+3)/(4*n+3).
EXAMPLE
For n=0, there is just one square, so that a(0)=1. For n=1, one can dissect an octagon in 8 ways into a hexagon and a square. In this case, the equivalence relation just relates every such dissection to its half rotated image, so that a(1)=4.
MATHEMATICA
Table[Binomial[5*n + 2, n]*(n + 3)/(4*n + 3), {n, 0, 50}]
PROG
(Sage)
def A367872(n):
return binomial(5*n+2, n) * (n+3) / (4*n+3)
(PARI) for(n=0, 25, print1(binomial(5*n+2, n)*(n+3)/(4*n+3), ", "))
CROSSREFS
KEYWORD
nonn
AUTHOR
F. Chapoton, Feb 22 2024
STATUS
approved