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A363924
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a(n) = number of k <= m such that rad(k) | m, where m = A005117(n) and rad(n) = A007947(n).
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1
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1, 2, 2, 2, 5, 2, 6, 2, 2, 6, 5, 2, 2, 5, 7, 2, 7, 2, 18, 2, 6, 8, 5, 2, 8, 6, 2, 19, 2, 8, 2, 6, 2, 5, 6, 8, 2, 2, 8, 5, 22, 2, 6, 20, 2, 2, 9, 5, 23, 2, 9, 2, 5, 9, 7, 2, 5, 7, 9, 5, 2, 2, 25, 2, 16, 9, 2, 2, 21, 7, 2, 26, 5, 9, 5, 9, 7, 2, 7, 23, 2, 5, 10, 2
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OFFSET
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1,2
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COMMENTS
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Let S_m be the sequence { k : rad(k) | rad(m) }. This sequence gives the number of k <= rad(m), which is the same as k <= m, since m is squarefree. Seen another way, this sequence gives the position of m in S_m.
Number of k <= p^e, e >= 0, such that rad(k) | p is (e+1). This is given by {A025477} + 1.
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LINKS
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FORMULA
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For prime b(n) = p, a(n) = 2 since terms k in S_p such that k <= p are {1, p}.
For composite b(n) = m, a(n) > 2, since p | m appear in S_p, and p < m.
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EXAMPLE
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a(1) = 1 since 1 is the only number k <= b(1) such that rad(k) | 1.
a(2) = 2 since k in {1, 2} are such that rad(k) | 2.
a(5) = 5 since b(5) = 6, k in {1, 2, 3, 4, 6} are such that rad(k) | 6. That is, 6 appears in the 5th position in S_6 = A003586.
a(7) = 6 since b(7) = 10, Card({ k : k <= 10, rad(k) | 10 }) = Card({1, 2, 4, 5, 8, 10}) = 6. That is, 10 appears in the 6th position in S_10 = A003592, etc.
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MATHEMATICA
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rad[x_] := Times @@ FactorInteger[x][[All, 1]]; Map[Function[{m, r}, Count[Range[m], _?(Divisible[r, rad[#] ] &)]] @@ {#, rad[#]} &, Select[Range[2^10], SquareFreeQ]]
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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