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A363827
Highest power of 2 dividing n which is <= sqrt(n).
1
1, 1, 1, 2, 1, 2, 1, 2, 1, 2, 1, 2, 1, 2, 1, 4, 1, 2, 1, 4, 1, 2, 1, 4, 1, 2, 1, 4, 1, 2, 1, 4, 1, 2, 1, 4, 1, 2, 1, 4, 1, 2, 1, 4, 1, 2, 1, 4, 1, 2, 1, 4, 1, 2, 1, 4, 1, 2, 1, 4, 1, 2, 1, 8, 1, 2, 1, 4, 1, 2, 1, 8, 1, 2, 1, 4, 1, 2, 1, 8, 1, 2, 1, 4, 1, 2, 1, 8, 1, 2, 1, 4, 1, 2, 1, 8, 1, 2, 1, 4
OFFSET
1,4
FORMULA
a(n) = 2^min(A007814(n), A102572(n)). - Kevin Ryde, Oct 20 2023
MATHEMATICA
Table[Last[Select[Divisors[n], # <= Sqrt[n] && IntegerQ[Log[2, #]] &]], {n, 100}]
a[n_] := 2^Min[IntegerExponent[n, 2], Floor[Log2[n]/2]]; Array[a, 100] (* Amiram Eldar, Oct 19 2023 *)
PROG
(PARI) a(n) = if (n==1, 1, vecmax(select(x->((x^2 <= n) && (2^logint(x, 2)==x)), divisors(n)))); \\ Michel Marcus, Oct 19 2023
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Ilya Gutkovskiy, Oct 19 2023
STATUS
approved