OFFSET
0,2
REFERENCES
0
FORMULA
From Peter Bala, Mar 29 2023: (Start)
a(n) = Sum_{k = 0..n} binomial(n,k)^2*binomial(n+k,k)*binomial(n+k-1,k).
P-recursive: n^3*Q(n-1)*a(n) = 4*(204*n^6 - 1275*n^5 + 3178*n^4 - 3999*n^3 + 2667*n^2 - 910*n + 126)*a(n-1) - (n - 2)^3*Q(n)*a(n-2) with a(0) = 1, a(1) = 3 and where Q(n) = 24*n^3 - 42*n^2 + 28*n - 7.
a(n) ~ (1 + sqrt(2))^(4*n+1) / (2^(7/4)*(Pi*n)^(3/2)).
The supercongruence a(n*p^r) == a(n*p^(r-1)) holds for positive integers n and r and all primes p >= 5. (End)
MAPLE
MATHEMATICA
Table[HypergeometricPFQ[{-n, -n, n, n + 1}, {1, 1, 1}, 1], {n, 0, 20}] (* Vaclav Kotesovec, Mar 29 2023 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
Peter Luschny, Mar 27 2023
STATUS
approved