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A360111
a(n) = 1 if there is no prime p such that p^p divides n, but for the arithmetic derivative of n such a prime exists, otherwise a(n) = 0; a(1) = 0 by convention.
6
0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1, 0, 0, 0, 1
OFFSET
1
COMMENTS
Question: What is the asymptotic mean of this and sequences like A341996 and its complement A368915, and related A368916? - Antti Karttunen, Jan 11 2024
Question: Is the asymptotic mean of this sequence 1 - Product_{p prime} (1 - 1/p^(1+p)) = 0.13585792767780221591...? (I.e. complementary to that of A368916). But see also A368911. - Antti Karttunen, Jan 29 2024
FORMULA
a(n) = A359550(n) * A341996(n).
a(n) = [-1 == A256750(n)], where [ ] is the Iverson bracket.
For n > 1, a(n) = A359550(n) - A368915(n). - Antti Karttunen, Jan 11 2024
EXAMPLE
a(12) = 0, because for both 12 and 12' = A003415(12) = 16 there is a prime p (in both cases p=2) such that p^p divides them.
a(15) = 1, because 15 = 3*5 has no such prime divisor p that p^p would divide it, while 15' = 8 is divisible by 2^2.
MATHEMATICA
d[0] = d[1] = 0; d[n_] := n * Plus @@ ((Last[#]/First[#]) & /@ FactorInteger[n]); q[n_] := AllTrue[FactorInteger[n], Last[#] < First[#] &]; q[1] = True; a[1] = 0; a[n_] := If[q[n] && ! q[d[n]], 1, 0]; Array[a, 100] (* Amiram Eldar, Jan 31 2023 *)
PROG
(PARI)
A003415(n) = if(n<=1, 0, my(f=factor(n)); n*sum(i=1, #f~, f[i, 2]/f[i, 1]));
A359550(n) = { my(f = factor(n)); prod(k=1, #f~, (f[k, 2]<f[k, 1])); };
A360111(n) = ((n>1)&&A359550(n)&&!A359550(A003415(n)));
CROSSREFS
Characteristic function of A327934.
After n=1 differs from A360109 for the next time at n=81, where a(81) = 0, while A360109(81) = 1.
Differs from A353479 for the first time at n=158, where a(158) = 1, while A353479(158) = 1.
Sequence in context: A297044 A296213 A353479 * A359162 A327932 A373979
KEYWORD
nonn
AUTHOR
Antti Karttunen, Jan 31 2023
STATUS
approved