

A359010


Variant of the inventory sequence: Record the number of terms whose value occurs once thus far in the sequence, then the number of terms whose value occurs twice thus far, and so on; a row ends when a 0 that would repeat infinitely is reached.


0



0, 1, 0, 1, 4, 0, 1, 0, 3, 4, 0, 1, 2, 0, 4, 0, 2, 2, 6, 4, 0, 2, 0, 0, 12, 0, 3, 2, 0, 8, 5, 0, 4, 2, 0, 4, 0, 12, 0, 3, 2, 3, 8, 0, 6, 7, 0, 2, 6, 3, 4, 5, 0, 7, 8, 0, 0, 6, 3, 8, 0, 6, 7, 8, 0, 0, 4, 3, 4, 10, 0, 7, 8, 9, 0, 2, 4, 0, 8, 5, 0, 14, 0, 9, 10, 0
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OFFSET

1,5


COMMENTS

Note that we are counting terms with repetition. For example, to find a(5)=4, we are looking for the number of terms that appear twice. 0 and 1 each occur twice, which is 2+2=4 (not 1+1=2). This means that each column contains only multiples of the number of occurences it is counting.


LINKS



EXAMPLE

First few rows of irregular triangle:
0;
1, 0;
1, 4, 0;
1, 0, 3, 4, 0;
1, 2, 0, 4, 0;
2, 2, 6, 4, 0;
2, 0, 0, 12, 0;
3, 2, 0, 8, 5, 0;
4, 2, 0, 4, 0, 12, 0;
3, 2, 3, 8, 0, 6, 7, 0;
2, 6, 3, 4, 5, 0, 7, 8, 0;


CROSSREFS



KEYWORD

nonn,tabf


AUTHOR



STATUS

approved



