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A359010
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Variant of the inventory sequence: Record the number of terms whose value occurs once thus far in the sequence, then the number of terms whose value occurs twice thus far, and so on; a row ends when a 0 that would repeat infinitely is reached.
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0
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0, 1, 0, 1, 4, 0, 1, 0, 3, 4, 0, 1, 2, 0, 4, 0, 2, 2, 6, 4, 0, 2, 0, 0, 12, 0, 3, 2, 0, 8, 5, 0, 4, 2, 0, 4, 0, 12, 0, 3, 2, 3, 8, 0, 6, 7, 0, 2, 6, 3, 4, 5, 0, 7, 8, 0, 0, 6, 3, 8, 0, 6, 7, 8, 0, 0, 4, 3, 4, 10, 0, 7, 8, 9, 0, 2, 4, 0, 8, 5, 0, 14, 0, 9, 10, 0
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OFFSET
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1,5
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COMMENTS
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Note that we are counting terms with repetition. For example, to find a(5)=4, we are looking for the number of terms that appear twice. 0 and 1 each occur twice, which is 2+2=4 (not 1+1=2). This means that each column contains only multiples of the number of occurences it is counting.
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LINKS
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EXAMPLE
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First few rows of irregular triangle:
0;
1, 0;
1, 4, 0;
1, 0, 3, 4, 0;
1, 2, 0, 4, 0;
2, 2, 6, 4, 0;
2, 0, 0, 12, 0;
3, 2, 0, 8, 5, 0;
4, 2, 0, 4, 0, 12, 0;
3, 2, 3, 8, 0, 6, 7, 0;
2, 6, 3, 4, 5, 0, 7, 8, 0;
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CROSSREFS
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KEYWORD
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nonn,tabf
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AUTHOR
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STATUS
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approved
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