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A358256
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a(n) is the smallest primitive Niven number ending with n zeros.
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1
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1, 110, 1300, 17000, 790000, 59900000, 19999999000000, 2999999999999990000000, 4999999999999999999999999999900000000, 899999999999999999999999999999999999999999999999999999999000000000
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OFFSET
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0,2
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COMMENTS
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1 is a primitive Niven number, not ending with 0, so a(0)=1.
a(n) is the smallest term of A358255 that ends with n zeros for n > 0.
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LINKS
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Table of n, a(n) for n=0..9.
Giovanni Resta, Harshad numbers.
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FORMULA
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a(n) = A051885(2^n)*10^n for n > 3. - Rémy Sigrist, Nov 05 2022
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EXAMPLE
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1300 is divisible by 1+3=4, but 13 and 130 are not divisible by 4; 1300 is the smallest such integer ending with two 0's, so a(2) = 1300.
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CROSSREFS
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Cf. A005349, A051885, A358255.
Sequence in context: A248468 A231967 A232339 * A200877 A205348 A008450
Adjacent sequences: A358253 A358254 A358255 * A358257 A358258 A358259
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KEYWORD
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nonn,base
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AUTHOR
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Bernard Schott, Nov 05 2022
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STATUS
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approved
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