

A358256


a(n) is the smallest primitive Niven number ending with n zeros.


1



1, 110, 1300, 17000, 790000, 59900000, 19999999000000, 2999999999999990000000, 4999999999999999999999999999900000000, 899999999999999999999999999999999999999999999999999999999000000000
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OFFSET

0,2


COMMENTS

1 is a primitive Niven number, not ending with 0, so a(0)=1.
a(n) is the smallest term of A358255 that ends with n zeros for n > 0.


LINKS

Table of n, a(n) for n=0..9.
Giovanni Resta, Harshad numbers.


FORMULA

a(n) = A051885(2^n)*10^n for n > 3.  Rémy Sigrist, Nov 05 2022


EXAMPLE

1300 is divisible by 1+3=4, but 13 and 130 are not divisible by 4; 1300 is the smallest such integer ending with two 0's, so a(2) = 1300.


CROSSREFS

Cf. A005349, A051885, A358255.
Sequence in context: A248468 A231967 A232339 * A200877 A205348 A008450
Adjacent sequences: A358253 A358254 A358255 * A358257 A358258 A358259


KEYWORD

nonn,base


AUTHOR

Bernard Schott, Nov 05 2022


STATUS

approved



