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A358181
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Decimal expansion of the real root of x^3 - 2*x^2 - x - 1.
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3
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2, 5, 4, 6, 8, 1, 8, 2, 7, 6, 8, 8, 4, 0, 8, 2, 0, 7, 9, 1, 3, 5, 9, 9, 7, 5, 0, 8, 8, 0, 9, 7, 9, 1, 5, 2, 8, 8, 1, 1, 2, 7, 0, 3, 3, 7, 4, 5, 2, 0, 0, 6, 1, 2, 9, 5, 5, 1, 4, 7, 4, 5, 7, 4, 7, 1, 1, 1, 9, 7, 9, 8, 3, 1, 3, 1
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OFFSET
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1,1
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COMMENTS
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This equals r0 + 2/3 where r0 is the real root of y^3 - (7/3)*y - 61/27.
The other roots of x^3 - 2*x^2 - x - 1 are (2 + w1*((61 + 9*sqrt(29))/2)^(1/3) + w2*((61 - 9*sqrt(29))/2)^(1/3))/3 = -0.2734091384... + 0.5638210928...*i, and its complex conjugate, where w1 = (-1 + sqrt(3)*i)/2 = exp(2*Pi*i/3) and w2 = (-1 - sqrt(3)*i)/2 are the complex conjugate roots of x^3 - 1.
Using hyperbolic functions these roots are (2 - sqrt(7)*(cosh((1/3)*arccosh((61/98)*sqrt(7))) - sqrt(3)*sinh((1/3)*arccosh((61/98)*sqrt(7)))*i))/3, and its complex conjugate.
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LINKS
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FORMULA
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r = (2 + ((61 + 9*sqrt(29))/2)^(1/3) + 7*((61 + 9*sqrt(29))/2)^(-1/3))/3.
r = (2 + ((61 + 9*sqrt(29))/2)^(1/3) + ((61 - 9*sqrt(29))/2)^(1/3))/3.
r = 2*(1 + sqrt(7)*cosh((1/3)*arccosh((61/98)*sqrt(7))))/3.
r = (2/3) +(2^(2/3)*61^(1/3))/3*Hyper2F1([-1/6,1/3],[1/2],2349/3721). - Gerry Martens, Nov 08 2022
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EXAMPLE
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2.5468182768840820791359975088097915288112703374520061295514745747111979831...
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MATHEMATICA
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RealDigits[x /. FindRoot[x^3 - 2*x^2 - x - 1, {x, 2}, WorkingPrecision -> 120]][[1]] (* Amiram Eldar, Nov 08 2022 *)
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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