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A357625
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Numbers k such that the k-th composition in standard order has half-alternating sum 0.
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20
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0, 14, 15, 44, 45, 46, 52, 53, 54, 59, 61, 152, 153, 154, 156, 168, 169, 170, 172, 179, 181, 185, 200, 201, 202, 204, 211, 213, 217, 230, 231, 234, 235, 239, 242, 243, 247, 254, 255, 560, 561, 562, 564, 568, 592, 593, 594, 596, 600, 611, 613, 617, 625, 656
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OFFSET
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1,2
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COMMENTS
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We define the half-alternating sum of a sequence (A, B, C, D, E, F, G, ...) to be A + B - C - D + E + F - G - ...
The k-th composition in standard order (graded reverse-lexicographic, A066099) is obtained by taking the set of positions of 1's in the reversed binary expansion of k, prepending 0, taking first differences, and reversing again. This gives a bijective correspondence between nonnegative integers and integer compositions.
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LINKS
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EXAMPLE
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The sequence together with the corresponding compositions begins:
0: ()
14: (1,1,2)
15: (1,1,1,1)
44: (2,1,3)
45: (2,1,2,1)
46: (2,1,1,2)
52: (1,2,3)
53: (1,2,2,1)
54: (1,2,1,2)
59: (1,1,2,1,1)
61: (1,1,1,2,1)
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MATHEMATICA
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stc[n_]:=Differences[Prepend[Join @@ Position[Reverse[IntegerDigits[n, 2]], 1], 0]]//Reverse;
halfats[f_]:=Sum[f[[i]]*(-1)^(1+Ceiling[i/2]), {i, Length[f]}];
Select[Range[0, 100], halfats[stc[#]]==0&]
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PROG
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(Python)
from itertools import count, islice
def comp(n): #row n of A066099 after Franklin T. Adams-Watters
v, k = [], 0
while n > 0:
k += 1
if n%2 == 1:
v.append(k)
k = 0
n = n//2
return(v[::-1])
def a_gen():
for n in count(0):
c = comp(n)
x = sum(c[i]*(-1)**(i//2) for i in range(len(c)))
if x == 0:
yield(n)
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CROSSREFS
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See link for sequences related to standard compositions.
The version for full alternating sum is A344619.
The version for prime indices is A357631.
The version for Heinz numbers of partitions is A357635.
A124754 gives alternating sum of standard compositions, reverse A344618.
Cf. A001511, A053251, A357136, A357182, A357183, A357184, A357185, A357622, A357623, A357629, A357633.
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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