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A353542 a(n) is the least start of a run of n consecutive numbers whose abundancy index is larger than Pi^2/6. 0
4, 44, 188, 8110374, 330921744 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,1
COMMENTS
By the Chinese Remainder Theorem, a(n) exists for all n. The proof is similar to the proof that is given for A094268.
LINKS
EXAMPLE
a(1) = 4 since 4 is the least term of A353537.
a(2) = 44 since 44 is the least term of A353538.
CROSSREFS
Sequence in context: A053314 A051223 A330651 * A265081 A077435 A271294
KEYWORD
nonn,more
AUTHOR
Amiram Eldar, Apr 25 2022
STATUS
approved

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Last modified July 13 14:24 EDT 2024. Contains 374284 sequences. (Running on oeis4.)