|
|
A352986
|
|
a(n) = Sum_{k=0..floor(n/3)} k^(3*(n-3*k)).
|
|
0
|
|
|
1, 0, 0, 1, 1, 1, 2, 9, 65, 514, 4124, 33498, 281829, 2628658, 31130220, 521900363, 11550872369, 292093228523, 7763038391586, 210839178560483, 5844964107402065, 168148032885913260, 5206234971937519704, 183267822341124743772, 7684147885975909244473
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
0,7
|
|
LINKS
|
|
|
FORMULA
|
G.f.: Sum_{k>=0} x^(3 * k) / (1 - k^3 * x).
a(n) ~ sqrt(2*Pi) * (n/(3*LambertW(exp(1)*n/3)))^(3*n + 1/2 - 3*n/LambertW(exp(1)*n/3)) / (3*sqrt(1 + LambertW(exp(1)*n/3))). - Vaclav Kotesovec, Apr 14 2022
|
|
MATHEMATICA
|
a[0] = 1; a[n_] := Sum[k^(3*(n - 3*k)), {k, 0, Floor[n/3]}]; Array[a, 25, 0] (* Amiram Eldar, Apr 13 2022 *)
|
|
PROG
|
(PARI) a(n) = sum(k=0, n\3, k^(3*(n-3*k)));
(PARI) my(N=40, x='x+O('x^N)); Vec(sum(k=0, N, x^(3*k)/(1-k^3*x)))
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn,easy
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|